General Questions
Practice and master this topic with our carefully crafted questions.
| Part filled by A in 1 min = | 1 | . |
| 20 |
| Part filled by B in 1 min = | 1 | . |
| 30 |
| Part filled by (A + B) in 1 min = | ![]() |
1 | + | 1 | ![]() |
= | 1 | . |
| 20 | 30 | 12 |
Both pipes can fill the tank in 12 minutes.
| Net part filled in 1 hour | ![]() |
1 | + | 1 | - | 1 | ![]() |
= | 17 | . |
| 5 | 6 | 12 | 60 |
The tank will be full in |
60 | hours i.e., 3 | 9 | hours. |
| 17 | 17 |
| Part filled by (A + B + C) in 3 minutes |
| = 3 | ![]() | 1 | + | 1 | + | 1 | ![]() | = | ![]() | 3 x | 11 | ![]() | = | 11 | . |
| 30 | 20 | 10 | 60 | 20 |
| Part filled by C in 3 minutes = | 3 | . |
| 10 |
| Part filled by C in 3 minutes = | 3 | . |
| 10 |
Required ratio = |
![]() |
3 | x | 20 | ![]() |
= | 6 | . |
| 10 | 11 | 11 |
Suppose, first pipe alone takes x hours to fill the tank .
Then, second and third pipes will take (x -5) and (x - 9) hours respectively to fill the tank.
|
1 | + | 1 | = | 1 |
| x | (x - 5) | (x - 9) |
|
x - 5 + x | = | 1 |
| x(x - 5) | (x - 9) |
(2x - 5)(x - 9) = x(x - 5)
x2 - 18x + 45 = 0
(x - 15)(x - 3) = 0
x = 15. [neglecting x = 3]
Let the slower pipe alone fill the tank in x minutes.
| Then, faster pipe will fill it in | x | minutes. |
| 3 |
|
1 | + | 3 | = | 1 |
| x | x | 36 |
|
4 | = | 1 |
| x | 36 |
x = 144 min.
| Work done by the waste pipe in 1 minute |
| = | 1 | - | ![]() | 1 | + | 1 | ![]() |
| 15 | 20 | 24 |
| = | ![]() |
1 | - | 11 | ![]() |
| 15 | 120 |
| = - | 1 | . [-ve sign means emptying] |
| 40 |
Volume of |
1 | part = 3 gallons. |
| 40 |
Volume of whole = (3 x 40) gallons = 120 gallons.
| Part filled in 4 minutes = 4 | ![]() |
1 | + | 1 | ![]() |
= | 7 | . |
| 15 | 20 | 15 |
| Remaining part = | ![]() |
1 - | 7 | ![]() |
= | 8 | . |
| 15 | 15 |
| Part filled by B in 1 minute = | 1 |
| 20 |
|
1 | : | 8 | :: 1 : x |
| 20 | 15 |
| x = | ![]() |
8 | x 1 x 20 | ![]() |
= 10 | 2 | min = 10 min. 40 sec. |
| 15 | 3 |
The tank will be full in (4 min. + 10 min. + 40 sec.) = 14 min. 40 sec.
minutes and 45 minutes respectively. Both pipes are opened. The cistern will be filled in just half an hour, if the B is turned off after:Let B be turned off after x minutes. Then,
Part filled by (A + B) in x min. + Part filled by A in (30 -x) min. = 1.
x |
![]() |
2 | + | 1 | ![]() |
+ (30 - x). | 2 | = 1 |
| 75 | 45 | 75 |
|
11x | + | (60 -2x) | = 1 |
| 225 | 75 |
11x + 180 - 6x = 225.
x = 9.
hours to fill the tank. The leak can drain all the water of the tank in:
| Work done by the leak in 1 hour = | ![]() |
1 | - | 3 | ![]() |
= | 1 | . |
| 2 | 7 | 14 |
Leak will empty the tank in 14 hrs.
| Part filled by (A + B) in 1 minute |
| = | ![]() | 1 | + | 1 | ![]() | = | 1 | . |
| 60 | 40 | 24 |
Suppose the tank is filled in x minutes.
| Then, | x | ![]() |
1 | + | 1 | ![]() |
= 1 |
| 2 | 24 | 40 |
|
x | x | 1 | = 1 |
| 2 | 15 |
x = 30 min.

