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A team of 8 students goes on an excursion, in two cars, of which one can seat 5 and the other only 4. In how many ways can they travel? |
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Answer: Option C Explanation: There are 8 students and the maximum capacity of the cars together is 9. We may divide the 8 students as follows: Case I: 5 students in the first car and 3 in the second Case II: 4 students in the first car and 4 in the second Hence, in Case I: 8 students are divided into groups of 5 and 3 in 8C3 ways. Similarly, in Case II: 8 students are divided into two groups of 4 and 4 in 8C4 ways. Therefore, the total number of ways in which 8 students can travel is: (8C3 + 8C4) = 70 + 56 = 126 |
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